770=-16x^2+1700

Solution for 770=-16x^2+1700 equation:

770=-16x^2+1700

We move all terms to the left:

770-(-16x^2+1700)=0

We get rid of parentheses

16x^2-1700+770=0

We add all the numbers together, and all the variables

16x^2-930=0

a = 16; b = 0; c = -930;
Δ = b2-4ac
Δ = 02-4·16·(-930)
Δ = 59520
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{59520}=\sqrt{64*930}=\sqrt{64}*\sqrt{930}=8\sqrt{930}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{930}}{2*16}=\frac{0-8\sqrt{930}}{32}
=-\frac{8\sqrt{930}}{32}
=-\frac{\sqrt{930}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{930}}{2*16}=\frac{0+8\sqrt{930}}{32}
=\frac{8\sqrt{930}}{32}
=\frac{\sqrt{930}}{4}
$